Form display with a function

[Anon]

This is a part of a larger script.

<?php

function display_form()
{

echo &#34;<form action=login.php3 method=post>";

echo &#34;Login Name:<input type=text name=login value=$login>";

echo &#34;<input type=submit name=submit value=Login></form>";
}
...
display_form();
?&#62;

---

What the above does is that it displays the form WITHOUT the login field already filled in with $login.

However, if I do not use a function to display the form, that form is shown with the login field filled in as expected.

I have many scripts that require forms to be displayed several times depending on the condition. So not being able to use a function to display the form makes the script really large and unprofessional.

Can somebody tell me why the function does not display a form with the data already filled in? Thanx.

Richie.

[deckrdx]

Either make login a global variable in the function...

global $login;

... or pass it as a variable...

function display_form($login='') {

[Anon]

Because the data is stored in a variable which is not within the scope of the function. try: function display_form($login)
or:
function display_form()
global $login;
This should allow the variable to be visible within the function/

[lucidfx]

or pass the variable to the function.

function display_form(&$login)
{

echo "<form action=login.php3 method=post>";

echo "Login Name:<input type=text name=login value=$login>";

echo "<input type=submit name=submit value=Login></form>";
}

display_form($login);

[Anon]

Thank you guys. I appreciate the help.

Richie.