replacing content

lazzerous

Hello there - I'm trying to use the eregi_replace() function, and having no luck.

Please - take a look at my code and let me know what I'm overlooking.

while ($myrow=mysql_fetch_array($desc)){
for($m = 0; $m < count($words); $m++) {
echo "$m \n";
$paco = eregi_replace($words[$m], "<font color='red'><b>$words[$m]</b></font>", $myrow[0]);
echo "<input type=hidden name=words1[] value=\"$words[$m]\">\n";
}
}
echo "<table><tr><td bgcolor=\"#eeeeee\">$paco<br><br>\n";

$words is an array
$desc is a mysql query selecting info from a database
I did verify that both $words and $desc contain values

Any ideas?

Thank,
Joe

Anon

above your for loop, put
$paco = $myrow[0];

let me know how it works...

-paul
http://xhawk.net

Anon

($words[$m], "$words[$m]", $myrow[0]);
echo "\n";

in that line I belive the problem is you put quotes around "$words[$m]" and you shouldn't for a variable so when it sees $words it doesn't replace it with the variable $words[$m] it actully replaces it with the word "$words[$m]" so try this instead.

while ($myrow=mysql_fetch_array($desc)){
for($m = 0; $m < count($words); $m++) {
echo "$m \n";
$paco = eregi_replace($words[$m], $words[$m], $myrow[0]);
echo "<input type=hidden name=words1[] value=\"$words[$m]\">\n";
}
}
echo "<table><tr><td bgcolor=\"#eeeeee\">$paco<br><br>\n";