conditional image

[Anon]

I am trying to display an image stored in a DB based on whether it is there or not. Here is my code:

if ($row["image_path"] == 0){
print("");
}else{
print("<img src=" . $row["image_path"] . " align=" . "right" . ">");
}

however it always prints ("") no matter what, how do I say "if $row[image] is null, then...

any help would be appreciated.

[frymaster]

try testing for NULL or "" instead of 0.