posting an array of fields to a form???

[Anon]

I am trying to post fields which are selected by checkbox, so that they will be displayed on the next page, new.php4. this is the code I am using and it doesn't seem to be print out the selected fields on the new page. could anyone help??

<FORM METHOD = post ACTION = new.php4)

for ($i=0; $i < mysql_num_fields ($result); $i++)
{
print("<TR><TD>");
$name = mysql_field_name ($result, $i);
print ("$field\n");
$row[] = $field;
print("</TD><TD>");
printf("<INPUT type=checkbox name=$field] value=$field>"
if(strstr($row["permission"], $field)) print("CHECKED");
print("</TD></TR>");
}

</FORM>

[Anon]

If that's a direct copy of your code then you have a typo.
<b>printf("<INPUT type=checkbox name=$field] value=$field>"</b>

Needs to be
<b>printf("<INPUT type=checkbox name=$field[] value=$field>"</b>

[Anon]

that was a typo

[Anon]

Ok so I looked at it again, and I see you using the variable $field all over the place, but I don't see where that variable get's set. You do set the variable $name to be your current row's result. Maybe that's your problem.