getimagesize issue

Anon

I am reading a list of image file names into an array, then using that array to display the images one by one. I am attempting to use getimagesize($image) to get the size of each image, but I keep getting the error "Unable to open /home/sites/sitex/web/directory/pic.jpg". 
The strange thing is, if I copy the path in the error message and stick it back in thusly: 
getimagesize('/home/sites/sitex/web/directory/pic.jpg'); 
it works just fine. Also doing something like: 
$dir = '/home/sites/sitex/web/directory/'; 
getimagesize($dir . 'pic.jpg'); 
works. Oddly enough, I have a different virtual host on the same server wherein the first type of example works fine. I have tried to make sure there are no weird permissions issues by matching everything to the site that works. 
Someone please tell me what stupid mistake I am making so that I can get on with my life 🙂
 
Setup info: 
PHP 4.0.3pl1 configured as a static Apache module 
Apache 1.3.14 
mod_ssl 2.7.1 
OpenSSl 0.9.6

terje-s

I have used getimagesize() for various purposes and never encountered anything similar. Can you paste the code?

Anon

Here is the outline of the code that doesn't work:

<?php
$startdir = '/home/sites/sitex/web/directory/';

$PicArray = file($startdir . 'pics.txt');

if (!isset($count)) {
$count = 0;
}

$image = $PicArray[$count];

$imagehw = GetImageSize($startdir . $image);

$imagewidth = $imagehw[0];
$imageheight = $imagehw[1];

The image specified in the image tag with the variable $image does show up, so I am fairly confident that there is nothing broken in the method for getting the picture. Also remember, that if I put a string (copied from the error message itself) in place of $image, it works fine ($imagehw = GetImageSize($startdir . 'pic.jpg') works fine).

Anon

Try this:

for ($z = 0; $z < strlen($imgName); $z++)
print '"'.$imgName[$z].'" ';

(set $imgName to $startdir . $image). Most likely you will discover that there is a blank (ascii 32) character at the end of your string. Hence, try trim($startdir . $image) :-)

Anon

Apparently that was the case. I knew it was something stupid..... trim() fixed everything. I appreciate your help.

Anon

I am having the same problem ... even after using trim()

Anon

make sure you are giving the path of the image from the root of the server, not the root of the site(virtual server)

that's what fixed it for me.