passing variables to functions

[junebug]

okay, i have a function like this:

function readfile($location, $var)
{
...
}

now i want to call the function and this is what i have:

$file = readfile($misc[include]."/file.inc", "1");

okay, now the $misc[include] is my include directory. it gives me a parse error though, and i have tried many ways with no avail. is there anyway around this aside from setting a variable with the pathname?

thanks in advance.

[Anon]

hi chris,
in your function the variable location should have the value "/your_include_dir/file.inc", what you intend to do does work ! For Example:
CreateThumbnail($the_server_path.$sThePicSrc, $the_server_path.'/pressepics/thumbs/'.$arrPics_name[$i], $iThumbH, $iThumbW)
works perfect for me ... so i would try to echo the value of $location in the function, to see if this is correct (maybe you have something like "/your_include_dir//file.inc") ...

hope that helps
cya Rob