preg_replace Question

Anon

Hi,

I have the following bit of code that's giving me a parse error in the preg_replace line :

<?php

$search = "JPG";
$replace = "jpg";

$dirPath = opendir("images/test/");
while ($file = readdir($dirPath)) {
if ($file != "." && $file != "..") {
echo "$file";
newfile$ = preg_replace ($search, $replace, $file);
echo "$newfile";
}
}

This should work as near as I can tell! Anybody have any suggestions?

Thanks!

Anon

Drunk ??!

newfile$ = preg_replace ($search, $replace, $file);

i guess if you put the $ on the right end of the newfile it'll work 🙂

$newfile = preg_replace ($search, $replace, $file);

cya Rob

Anon

Rob,

Ya, that would help. After changing it I get the following :

thm_DCP_2556.JPG
Warning: Delimiter must not be alphanumeric or backslash in rename.php3 on line 10

thm_DCP_2556.JPG is the file that preg_replace is trying to do its job on.

Anon

Hi Mark,

I'm short before sleeping, and my testserver is at work ... and I never used the preg_replace function ...
so i can't tell you whats wrong... I guess its something with the 4th (and optional) parameter "limit" ... but if you only need a replace function for that sort of stuff (nothing exotic) why don't you just use the popular: str_replace (search, replace, subject)?? http://www.php.net/manual/en/function.str-replace.php
This one works pretty reliable for me ...

cya Rob

Anon

Rob,

str_replace was exactly what I needed. Surprised I didn't see that function at php.net in the first place!

Thanks,

Mark