link to other php script

[Anon]

Hi folks,

sorry, I'm a beginner and this might just sound too stupid to you, but can anybody help me?

I wanna have an if-statement in one of my php files that then links the user to the
php-file A or B.

if (variable=="yes")
{
//goto version_a.php
}
else
{
//goto version_b.php
}

is there any possibility to make this with php?
I know that include does almost the same, but then I would still be in the same file and not really in the other one. (-> Problem if the other file is in another folder and refers to images)

Thanks for your help and sorry for this easy question 🙂

Chris van dyk

[Anon]

just use this:
header("Location: version_a.php");
and so on...

-paul
http://xhawk.net

[frymaster]

paul's idea is the best (only?) way. However, if you do something like this:

print "foo";
header("Location: someotherpage.php");

php will become very upset. Calling print will automatically send a text/html header to the browser, so when you try to send a second header with the header() call, things get ugly. The best way to get around this is to buffer your php output (ie store it in server ram until ALL php parsing and execution is done, then send it) that way, a header() call will override implicit text/html headers. make sense?

This is done by calling ob_start() at the beginning of your page (start buffering) and ob_end_flush() at the very end of your page. It's a good practice to get into and will save you headaches in the future.