Class can someone take look at mycode

Anon

Hi, I created a small class and when I run it i get the following error.
Parse error: parse error, expecting `')'' in Error.php3 on line 10

I am getting an errow when I try to pass a value to Errormessg function.
Can some help with this problem.

Here my class code.

<?php
class Error {

var $error;
     function Error( ) {
          $this->error=88;
     }

  function Errormessg($this->error) //this is line 10 where it gives me error
    {
      echo(\"NEVER GET HERE\");
    }

}
?>
----------------------------testfiel------------------
<?php
require(\"Error.php3\");
echo(\" TESTING CLASS<br>\");
$test=new Error();
$test-> Errormessg(1);
?>

Anon

its not on line 10 its above in your function definition - get rid of space in Error ( )

Anon

hi, I remove the space in the Error() and it I get the same error messg.

<?php
class Error {
var $error;
function Error() {
$this->error=88;
}
function Errormessg($this->error)
{
echo(" NOT ERROR ONE");
}
}
?>

Anon

You can't have $this->error as a parameter in a function declaration.

Anon

Try this... See explanation below.

<?php
class Error {

var $error;

function Error() {
$this->error=88;
}

function Errormessg() //this is line 10 where it gives me error
{
echo $this->error;
}
}
?>

You can't use $this->error inside the class as a parameter for a function call.

your Error() function is used to set the error.

Your Errormessg() is used to display the error.

Anon

don't use $this->error as your argument within a class method.

It has local scope, so just $myarg, and then you can reference $this->myerror inside the function (or not pass it an arg at all in this case.

R
<?
header("Content-type: text/plain");
echo "\n\n\n\n";
error_reporting(31);
$err = 'ito';

/ class MyError {
var $myerror;
function MyError() {
$this->myerror=88;
return $this->myerror;
}
function Errormessg($this->myerror) {
echo(" NOT ERROR ONE");
}
} /
class MyError {
var $myerror;
function MyError() {
$this->myerror=88;
}
function Errormessg($myarg) {
$this->myerror=$myarg;
}
}
$err = new MyError;
echo "result:".$err->myerror." ";
$err->Errormessg(99);
echo "New result:".$err->myerror." ";
?>