global var in function

[Anon]

Hi all
Can someone point out the errors of my ways, it's late so I expect itøs somthing stupid but I just canøt see it!

Problem is $empty wont print()?

$empty="You are missing a field!<br>go back and check everythings in order.";

function check_head_fields() {
global $field, $empty;
for ($i=1; $i<6; $i++) {
if (empty($field[$i])) {
print($empty);
exit;
}
$field[$i]=addslashes($field[$i]);
}
}

Cheers

Nick

[Anon]

It seems like you need to declare $field in the same place you are declaring $empty. You declare the usage of the global variable $empty in your function,
but does the variable actually exist yet?

[Anon]

A simple way to find out what's going on is to actually print the whole array.

[Anon]

Yes!
If you check the post you can see $empty just above the function.

Nick

[knickerlas]

Hi
It's not an array problem! $empty wont display, it is just a meesage saying that a feild is missing. That part of the function works perfectly.

Nick

[Anon]

Okay folks
I'm using this function in a script that prints out forms using PHP_SELF as the 'action' and sessions for some of the Vars.
If I session register $empty it works!

But why?

Thanks for the help

Nick

[Anon]

have you tried 'globalizing' your variable before the function is called? like...

global $empty;
$empty="You are missing a field!<br>go back and check everythings in order.";

function check_head_fields() {
global $field, $empty;
for ($i=1; $i<6; $i++) {
if (empty($field[$i])) {
print($empty);
exit;
}
$field[$i]=addslashes($field[$i]);
}
}