where is the error???

mojo85

ok I want my website to check if a user is logged in. If the user is logged in, then it would show the whole website and the Hello, BLAH BLAH messege....(I have figured this out allready) and if the user is not logged in, then it would show the whole page and the login Form...
But When I do this I get a Parse Error on line where there are ** on the line
here is my code...

PHP:--------------------------------------------------------------------------------

//Before This is the Website
<?php
if (!$HTTP_COOKIE_VARS["bbuserid"]) {
Print "Hello $username, and Welcome to our site!";
}
else
{
echo "
//Displly Login Part
**<TD width="153" valign="top" rowspan="7" height="458">
<center>
Login 
<img src="spacer2.jpg" align="top" width="90" height="1">   
<form action="/member.php" method="post">
Username:
<input type="text" name="username" size="12"maxlength="20">
 
Password: <input type="password" name="password"size="12" maxlength="15"><inputtype="hidden" name="action" value="login">
 
 
<input type="submit" name="submit" value="Login »">

";
}
?>

//Displly rest of Site

So can some one plz tell me what is wrong.....I'm a Newbie to PHP

Thanks in Advance

mojo85

what the...??
why is the page white...maybe its the html in it. just Highlight the text to see the code
watting for a reply
thanx

polson

you can't do this :

echo "foo"foo"foo";

You can do this :

echo "foo'sfoo'sfoo's";

echo 'foo"sfoo"sfoo"s';

echo <<<FOO
foo's bar"sfoooo"s
FOO;

Have a look at these places :

http://www.php.net/manual/en/language.types.string.php
http://www.zend.com/zend/tut/using-strings.php

mikeq

Hi,

Within your echo quotes you must escape all other double quotes by putting a \\ in front of them.

i.e.

echo \\"
//Displly Login Part
**<TD width=\\\\"153\\\\" etc...

\\";

mojo85

Thanx Guys for the Great Help...now I wil pass of the knowledge 😉