php parser skips jpg images ?

rkwvogel

Hello,

built a line like

print "<img src=\"objects/".$row["bildname"].
         ".jpg\" alt=\"\" border=\"1\">";

within a mysql query.
(Doesn't matter, can even be a pure php line)
But there are several (and allways the same) images that are not displayed in the output php-file.

If I store this output as a html file and start it from the explorer (i.e. without php), all images can be seen.
(Of course, same directory)

There are some error messages from php, when I try to display a missing image by klicking on 'View Image' (right mouse):

Warning: Unexpected character in input: '\' (ASCII=92) state=1 
in c:\phpweb//casa/objects/mallorca.jpg on line 47

and

Parse error: parse error in c:\phpweb//casa/objects/mallorca.jpg 
on line 47

(Correctly displayed images show the usual character salad.)

Does PHP try to interprete some image information ?
(The error is not due to any image name characteristic.)
How can get PHP to display them correctly ?

Thanks

Rainer

Anon

What is the code at line 47? My guess is that the value of $row["bildname"] has some characters in it that needed to be escaped for the database to store them and these escapes are what is causing the problem.

rkwvogel

Definitely it's not the code:
when I e.g. change the size of the image a little bit within a graphic program and store it , the new one may be displayed correctly.
So I succeeded with 8 of 10, but the two remaining keep unvisible,
no way what I try.
And later there will be an upload of images directly by the customer.
So until then I need to find out the reason for that bug.

Rainer