Regular Expressions

Anon

Need help with trying to format some ouptut deploying "sed" to remove everything in a line after a certain string is found.
What I've got that works is:
cd /misc/export/home/sgordon
sed -e "s/\/view\/past_view\///g" postfile > sedfile
The output is successful, but I want it to
remove the rest of the line as well.
Here's my output so far. (A parial output)
ac/Version-1.5/Docs/Integration/External API - 3 Tier URL Syntax.doc and vobs/ac/Version-1.5/Docs/Integration/External API - 3 Tier URL Syntax.doc differ

I want to remove everything AFTER the "and".
How do I do this?
Thanks,
Susan Gordon

Anon

To clear everything after the first and simply do:

sed "s/and.*//" filename

That will output everything without the and and everything after that. Hope that helps.

Chris King

Anon

Thanks so much for a timely response. Never realized that much of the deployment of regular expressions NEVER EVER go according to the man pages. I intended for this to be much more difficult.
One remaining question:
In this example of sed "s/and.*//" filename
MOST UNFORTUNTATELY there is an "and" in "command", which is part of the directory structure, so that the execution of this sed command truncates the rest of the line.
An example:
ac/Version-1.5/publisher/Source/PublisherComm
. How do you specify "and" and only and"?
Again, very appreciative.
Cheers
Susan