confused about include()

Anon

I've read in previous posts that if I define a variable before including another file, that variable will be available to the inluded file.

However, in the following:

<?php
$page_header = "Colter Peterson Products";
include ("header.php");
include ("content_products.php");
include ( "footer.php");
?>
the "header file " doesnt print the $page_header variable.

Any help would be much appreciated!

brandonschnell

what does the code look like in header.php?

Anon

like this...

?php
include ("root.php");
?>

<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<link rel="stylesheet" href="<?php echo $root;?>stylesheets/main.css" type="text/css">
<link rel="stylesheet" href="<?php echo $root;?>stylesheets/home.css" type="text/css">

</head>

Anon

help!

Anon

Not sure.. but.. shouldn't there be a ; after the variable..??

Anon

well as far as i know include just includes the contents of the file header.php ,footer.php etc in ur php file where u use the include and the variabe is also present in the present php file only not in the included files.

Anon

Well...

?php
include ("root.php");
?>

needs to become

<?php
include ("root.php");
?>

unless that isn't just a cut and paste, the rest of the code looks fine, theres no ; needed in situations like that.

Try echoing the $page_header variable at different places to see where it stops working, and try putting it in a cookie to see if it can be read from that to see where its going wrong.