changing variable with for loop?

I'm trying to do something that's hard to explain, I'll show you the code I tried first then I'll explain:

for ($i=0;$i<5;$i++){
if ($i=0){
$test="1";
}
else{
$i;
}
}

I know the code is crap and wont work, but this iss what I want it to do:

I need the value for varaible $test to change within the loop. so for this case, if it works, it should go like $test=1234

so the echo will return 1234 .

Is this possible ?

Thanks!!!

This should work:

$test = "";
for($i=1;$i<=4;$i++) {
$test .= "$i";
}
echo $test;

Thanks a million!!

$explodemodel = explode(" ",$model);
$models = "";

$i=0;
while ($i < count($explodemodel)) {

if ($i=0){
	$model1 = "model LIKE" ." '%$explodemodel[0]%'";
	}
else {
$models .= "OR model LIKE" ." '%$explodemodel[$i]%'";
}

$i++;
}

echo"$model1,$models";

basically, this is for the SELECT WHERE statement. I exploded the model value and do search of model LIKE 'exploded[0,1,2,3..]' one by one..

this function gave me this error:

Fatal error: Allowed memory size of 8388608 bytes exhausted (tried to allocate 22 bytes

any idea how to fix it? Thanks.

btw, your original function works

if ($i=0) will always evaluate true(methinks).

if ($i==0) is what you want.

no I have to use i=0..

anyways, I fixed it.. couldnt use while loop, had to use for look.. and had to get rid of the reset value

Maybe this will enlighten you.

if ($i) would be easier...