Check Date

[bjblackmore]

I have 3 text boxs which are used for entering Day|Month|Year into 040601 format. Is there away of using date() to check that the textbox value isn't a previus date? Something like
$currentdate = (date("dmy"));
$selectdate = $day$month$year;
if (selectdate = < $currentdate) {
Print "Error Previos Date Selected"
return false;
} else {
return true;
}

[Anon]

At first glance :

Change your date expression format to
$year then $month then $day.

• replace
  "$selectdate = $day$month$year;"
  by
  "$selectdate = $year . $month . $day;"

• replace
  "$currentdate = (date("dmy"));"
  by
  "$currentdate = (date("ymd"));"

But, in doing this your date will be expressed in a two digits format, which will eventually lead to a true result if the user input something greter than 01 (like 99 ...). To address that, you shoud either write a simple test (like "if ($year>30) return false;" if you want to use your script till 2030) that could still lead to erroneous results, either use a four digits year format by using "$currentdate = (date("Ymd"));".

You will also have to make some data input format validation by checking if the input string is of the correct length and/or correct value. ie "if ($month>12) return false;"

And, of course, you shoud declare the global variables used in your function with something like "global $year, $month, $day;".

[bjblackmore]

Thanks for that, I'll give it a try.
The format validation shouldn't be a problem (hopefully) I have decided to use drop down menus, with 01 - 12 for month and 01 - 05 for year. No one will be entering dates about 2003 hopefully, but it allows room for expansion.
I can't use 4 digit year dates (sadly, would make things easier), becuase we have an internal system here, that only understands 2 digits. Which is why i need ddmmyy.
/voodoo