Form processing & if/else function

[Anon]

Hi,

I started on a small personal project to write a simple help-wizard for the visitors of my website.

In the first php-file I am showing them 2 or more options (radio buttons) in a form where they can choose the situation that is applicable to them.

for example:
$option1: looking for personal subscription
$option2: looking for business subscription

I created a second php-file (to show the results of the form-action).

I used the if and else function to display a different message in the 2nd php-file, depending on the selected option (1 or 2) by the visitor in the 1st php-file.

Problem is that my program always shows the text which belongs to option 2. Also if option1 was selected.

The form in my 1st php-file looks like this:

<form action="results.php" method="post">

Select the option which is applicable to you:

<input type="radio" name="subtype" checked value="option1"> <? echo $option1; ?><br>

<input type="radio" name="subtype" value="option2"> <? echo $option2; ?> <br>

<input type="submit" value="Proceed-->">

---

My if/else statements in the 2nd php-file (results.php) look like this:

<?

if (value=="option1") {
echo "<b>You selected that you are looking for a personal subscription</b>";
}

else {
echo "<b>You selected that you are looking for a business subscription</b>";
}

?>

I hope someone could help me out, since I am just starting with PHP. I do know that I can put this script in a single file by using showform(), but I'm just experimenting to get this little program to work.

regards,

John

[Anon]

Yes I had this problem too and never did solve it the correct way, I think. What I did was to change each name field of my radio form and set my if/else statements accordingly.

Then if subname = option1 echo "whatever" else if subname2 = option2 then echo "something else".

This then recognizes what is checked. The problem is someone can select both of the buttons at once when the names are different on the form

But you can also write a quick code to see if both are checked and just echo another statement saying you can only check one box.

I'm sure there is a better way.

[[deleted]]

I have no clue why you wrote this:

if (value=="option1")

but it should be this:

if ($subtype=="option1")

[Anon]

Vincent, it works perfectly now, thnx!

Why I put in value==?? Well, don't know to be honest. I am PHP-newbie, but learning fast.