date formatting help

Anon

I'm trying to convert the string 'Jun' to '06' using the date() function.

This code works on the windows version but fails on Linux. It returns '12' no matter what I provide as the timestamp argument. Any help is appreciated!

$monthpart = date('m', 'Jun');
echo "$monthpart <br>";

Anon

$mon = "Jun";
$datestamp = strtotime("10 " . $mon . "2001");
$monthpart = date("m", $datestamp);
echo $monthpart;

Anon

Thanks Dale! That will definitely do the trick. I was hoping for a one-step function for converting three letter string months to thier ordinal values (1-12). Looks like a good candidate for a UDF - I need the practice anyway! Thanks again for responding.

Anon

$mon = "Jun";
$datestamp = strtotime("10 " . $mon . "2001");
$monthpart = date("m", $datestamp);
echo $monthpart;

Try this:

$mon = "Jun";
$monthpart = date("m", strtotime("10 " . $mon . "2001"));