Still having problems with return()

[ipruthi]

Hi,

I posted the need for help the other day concerning return(). I am trying to return an array but the thing below (which is what someone suggested) isn't working:

function somefunction()
{
$valid = "valid";
$returned_id = $result[user_id];
return array($valid, $returned_id);
}
$myfield = somefunction();

And then I try to print all the arrays with:

print "$myfield[0]"; //Prints OK
print "$myfield[1]"; //Does not Print

And I am stuck with a problem here. It only carries the 1st value of the array. Does anyone know how to fix this??? In other words, how can I get to print both arrays returned by a function???

Thanx in advance.

[Anon]

It is because $result[user_id] has no value inside the function and hence the second element in the array is empty.

If you are assigning some value to $result[user_id] outside the function then u need to declare $result as global inside the function. In that case try the following and see whether it resolves ur problem.

function somefunction()
{
global $result;
$valid = "valid";
$returned_id = $result[user_id];
return array($valid, $returned_id);
}
$myfield = somefunction();

print "$myfield[0]";
print "$myfield[1]";

[ipruthi]

Ok man, now u got me to show you the whole code 🙂 I am sure that my $returned_id[user_id] is not empty. Here is the whole function. I use this function to get me data from mySQL regarding users. Yeah, users i said.. because I'm building a portal myself 🙂
Anyway, so the function below is supposed to return:
1- If a user exists (return "valid") and
2- If a user exists, return me his/her ID.

The function follows:

function checkIfUserExists( $login )
{
global $link;
$result = mysql_query( "SELECT user_id, username FROM users WHERE username='$login'",$link );
if ( mysql_fetch_array($result) )
{
$valid = "valid";
$returned_id = $result[user_id];
return array($valid, $returned_id);
}
else
{
$valid = "invalid";
return ($valid);
}
}
$myarray = checkIfUserExists($login);

print "$myarray[0]"; //this prints accordingly
print "$myarray[1]"; //does not even print

This is what I did. The first value of the array (the valid/invalid) thing works perfectly. But the second and last value of the array does is empty for some reason. Just to make sure, I checked on my DB to see if there REALLY is a user_id, and yes there is a user_id and it is set to 1 (the 1st user)... Please help me out.

Ilir

[Anon]

Try the following code and see whether it helps you

function checkIfUserExists( $login )
{
global $link;
$result = mysql_query( "SELECT user_id, username FROM users WHERE username='$login'",$link );
if ( $row=mysql_fetch_array($result) )
{
$valid = "valid";
$returned_id = $row[user_id];
return array($valid, $returned_id);
}
else
{
$valid = "invalid";
return ($valid);
}
}
$myarray = checkIfUserExists($login);

[ipruthi]

Thank You Bibin, you just helped me make a big step of improvement in my portal. Thanks a lot. If you wanna check it out, the temporary address is: www.beaconschool.org/~ipruthi/photography/site/site3/

and don't think it's over yet 🙂

Thanks again.
Ilir.