scheduled events

[Anon]

I'm not sure if I should be posting this to the Linux site or PHP site but here's the problem i've run into. I have a scheduled event on a page that I want to run everyday on my Linux RH7 Server (called mikestest.php).

I've changed the permission structure on my mikestest.php file to 755 and the good news is, I no
longer get the permission error. However, I do get another error as follows:

/var/www/html/mikestest.php: ?PHP
: No such file or directory
/var/www/html/mikestest.php: line 2: syntax error near unexpected token
getdate()'
/var/www/html/mikestest.php: line 2:$today = getdate();
'

I know this file exists as i've done a pwd as follows:
pwd mikestest.php
/var/www/html

Here's my crontab file (hopefully it helps)
55 12 0-6 /var/www/html/mikestest.php

Anyone else know why this is occurring or how I can fix this?

Thanks,
Mike

[bfears]

What does the first line of your php file look like? Did you remember to include:
#!/path/to/php?

---

/var/www/html/mikestest.php: ?PHP
: No such file or directory
/var/www/html/mikestest.php: line 2: syntax error near unexpected token
getdate()'
/var/www/html/mikestest.php: line 2:$today = getdate();
'

I know this file exists as i've done a pwd as follows:
pwd mikestest.php
/var/www/html

Here's my crontab file (hopefully it helps)
55 12 0-6 /var/www/html/mikestest.php

Anyone else know why this is occurring or how I can fix this?

Thanks,
Mike

[Anon]

Ok, so here's what my test file looks like. I've added that first line but i'm not sure if that's right.

#!/var/www/html/ <----NEW LINE ADDED
<?PHP
$today = getdate();
$year = $today['year'];

print "The year is $year<BR>";

if($year == 2001)
{
print "Year is equivalent. Email sent<BR>";
$to = "[e-mail]";
$subject = "Test of crontab";
$message = "If your receiving this, crontab test was successful";
mail($to, $subject, $message)
or print ("ERROR: crontab test failed");
}
else
print "Year is not equivalent<BR>";
?>

[ddgenius]

The first line needs to be the location of your PHP executable on the machine. You can determine this by typing "which php" on the command line. Assuming you have PHP compiled as CGI, it should return something like /usr/local/bin/php.
I use #!/usr/local/bin/php -q on most of my machines.. The -q suppresses the html garbage. Other than that, it should run.

KABOOM wrote:

Ok, so here's what my test file looks like. I've added that first line but i'm not sure if that's right.

#!/var/www/html/ <----NEW LINE ADDED
<?PHP
$today = getdate();
$year = $today['year'];

print "The year is $year";

if($year == 2001)
{
print "Year is equivalent. Email sent";
$to = "[e-mail]";
$subject = "Test of crontab";
$message = "If your receiving this, crontab test was successful";
mail($to, $subject, $message)
or print ("ERROR: crontab test failed");
}
else
print "Year is not equivalent";
?>