Passing var from JS &gt; PHP (without form)

Passing var from JS > PHP (without form)

Anon

On my page I make use of functions in PHP & Javascript. In one of my PHP functions I need to read a Javascript variable that gets used/setup in one of my Javascript functions.

In my PHP function, how read this Javascript variable? I don't want to keep reloading the page via a hidden FORM field because the HTML output from my page is very big and contains lot on images etc which will take a long time for the brower to reload each time.

chowdary

Hello,
This looks funny(Am i kidding).Javascript is Client side scripting and PHP is on server side then how can you get the value....I am wondering how do you want execute the PHP script without refreshing the page.......Do you want to execute PHP in the Browser?
I am sorry if i hurt you.....

eduard

but tells the same story the other way around.. What Ajay means.. you need (read: MUST) post the variable from a form, to handle with it in php. The other option is to parse all possibilities you want, into your webpage (javascript) and handle the information overthere. Anyway, there is nothing like a event handler for example built in php, simply because you can't executes php code locally, you need to send a http request over and over again.

Anon

There might be another possibility: You could try fetching images with query strings in their URLs. e.g.:

You will need to encode the values appropriately if they might contain characters that don't belong in a URL.

It might be best to set up an appropriate Content type and dummy return data in the PHP script. This technique could also use the document.location member of a window (e.g. popup window). It might also be wise to ensure (using Expires headers) that the script URL doesn't get cached.