$some = join(", ", $value); HELP!

Anon

Hi,

I'm building a website with a multiple input field from which all the selected values must get into 1 column. So I need to put all the values in 1 string. I tried to used this piece op code:
$inputorgaan = join(", ", $orgaan);

From I thought that $inputorgaan would contain all the values which were submitted in the $orgaan from the form. But it just didn't work. (Yes I used the name: orgaan[] for the field).

But I just keep getting:
Warning: Bad arguments to join() in /homes/i/indis/www/mysql/invoerscript_product.php3 on line 8

Does anyone know how to solve this or antoher piece of code which could to exactly the same?

Thanks in Advance,
Gabriel

kailien

For your form, the input tag name must be in an array form. I.E.

<input type=checkbox name=blah_array[] value=blah> Blah

<input type=checkbox name=blah_array[] value=blah1> Blah1

etc...

then on the submitted script, use implode() to convert the array into a string.

Kai

reagent

I'd use var_dump($orgaan) to see what this value is. it could be that it isn't an array (for one reason or another). also make sure that you aren't duplicating names in your cookie or session vars, as these may be used before your post data (depending on GPC order)

assuming a post operation, use this

var_dump($HTTP_POST_VARS['orgaan']);

you may also want to put:
error_reporting(E_ALL)

at the top of your script

hth.
p.