Replace String through Whole Array

Anon

I've been trying to replace parts of strings in a results set, without much success. I've tried using str_replace() and eregi_replace() at about every location in the following code and the offending strings are still there.

I simply want to remove the – or ’ parts from any instance of $row[title] or $row[body] and replace them with " - " or " ' " respectively.

Where does the str_replace() go???

My code is below - any help is greatly appreciated!

// replace the offending string
function replace_string($string) {
$string = str_replace("–", "-", "$string");
$string = str_replace("’", "'", "$string");
}

// iterate through results array
if (mysql_num_rows($result) != 0) {
while ($row = mysql_fetch_array($result))
{
?>

// print HTML output

<?php print "$row[title]"; ?></a> 
<?php print substr($row[body],0,70) ." . . ."; ?> 
<?php print "$row[article_date]"; ?>
<?php
}
?>

Anon

// print HTML output

$row[title] = replace_string($row[title]);
$row[body] = replace_string($row[body]);


<?php print "$row[title]"; ?></a> 
<?php print substr($row[body],0,70) ." . . ."; ?> 
<?php print "$row[article_date]"; ?>
<?php
}

It should go right there. And just a formatting suggestion, if you are goitg to do all of those print commands, just include your HTML in them instead of opening and closing <?php ?> a dozen times, it'll look nicer and be easier to read.

Anon

that wont work either... his replace string function doesn't return anything. the function has to

return($string);

at the end... $string isn't global, you are just editing the local version of $string inside the function, and when the function finished, the variable goes away

Anon

Oops, I guess I missed that in my first reading.