using multiple scripts

junebug

okay lets say i am working in script a. script a is just a big switch() that figures out what to do. then it sends information to script b, script b runs and returns the results to script a.

my question is how do you do this without including or reading the file in?

any help would be great. thank in advance.

cordex

You could do a header("Location: $location_st") where $location_st is the url of script b with the variables contained inline.

$locations_st = "http://www.mydomain.com/bin/scriptb.php?var1=val1&var2=val2&var3=val3";

[deleted]

Another question: why would you ever want to?

junebug

well i have built a very large script and i am trying to break it down. so basically there are individual scripts for each section. and the base script is just a big switch() that will figure out which script to use, send some variables to it, recieve back the information, then take the info, wrap it up in a nice little html template and spit it out to the browser.

i want to test it and see if it is faster this way then including sections in. also, i just want to know if i can do this.

and header("Location: ") won't work because i need the output of script b so i can format it.

cordex

You want the output of the script but you don't want to fread(), include() or require() it?

doesn't make sense to me.

[deleted]

Just include the extra scripts whenever they are needed.

If you really want to get data from other scripts, you will have to
start the other script up (through EXEC or SYSTEM) then talk to it through stdin/stdout, and process the data you got back.

Just starting that instance will probably take 5-10 times as long as including the script when the switch needs it.