Counting unique words

[Anon]

Hi,

Does someone have a code to count words?
The result should be something like this

$word[0] = ("one, 20");
$word[0] = ("no, 16");

thanks,

jeroen

[tinuviel]

Why don't you do something like:
$v_word = "one";
$pagefile = fopen($page, "r");
$data = fread($pagefile, filesize($page));
$data = addslashes($data);
$i=1;
if (eregi(" ".$v_word." ",$data, $out)){
$word[0] = ('$v_word,$i');
$i++;
}

[Anon]

Try splitting the file on white space with $wordlist = preg_split("/\s+/", $str); and then looping through the array and calling substr_count on your string for each word in the list. Might have to do something special to work around punctuation.

[renegade888]

You could probably do something like this assuming the array $data contains your original info and the other array $list contains all unique words.

for ($i=0; $i<length($data); $i++) {
$found = 0;
for ($j=0; $j<length($list); j++) {
if ($data[$i] == $list[j]) {
$found = 1;
break;
}
}
if (!$found) {
$list[] = $data[$i];
}
}

you could add a way to keep count if you want to as well, but this should give all unique words assuming no punctuation or special characters.