Date formating

[Anon]

How can I format a date that has the following format

2001-10-31

into the day before this day (2001-10-30)?

If I just try -1 it gives 2000 ??? Does anyone have an answer to my problem?

Thanks a lot allready!!

[Anon]

the easiest way you can do is is format it with ereg like this

$date = your value;
$regex = ereg ("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})", $date, $regs);
echo "$regs[3].$regs[2].$regs[1]";

[Anon]

One way is to get the Year, Month, and Date into separte variables.

Then use mtime to get the previous date...

$date1 = "2001-10-30";

$MM = date("m", strtotime($date1));
$DD = date("d", strtotime($date1));
$YY = date("Y", strtotime($date1));

$date2 = date("Y-m-d", mktime(0,0,0,$MM,$DD-1,$YY));

// The $DD-1 gets the day before

echo $date2 // $date1 minus 1 day

[Anon]

OR if you are getting the Date from a mysql database...

SELECT newdate AS DATE_SUB(Date_field, INTERVAL 1 DAY) FROM TABLE