is_int()

[jacinthe]

hi folks,

i'v been searching the forum, got an answer but was curious if there was another way...

i got a form, with a textfield, and i want to check if that field is an integer. The is_int() function don't work, because it is a text field, so it always return a string.

What was proposed on the message a read is to use ereg like that :

if (ereg("^-?[0-9]+$", $YOUR_TEST))
{
echo ("is and integer");
}
else
{
echo ("is not an integer");
}

And then the sender ask if there wouldn't be another way of doing that and nobody answer so...

someone got an idea?

thanx in advance,

Jacinthe

[rrijnders]

AFAIK, this is the only way.

-- Rich

[reagent]

try using is_numeric() instead

p.

[jacinthe]

what????????

[jacinthe]

working 🙂

[cordex]

I know two other simple methods at least (right off the top of my head):

gettype() (will return "integer" if the variable is an integer)
and, of course, is_numeric() as suggested by p. reagan

-Ben

[rrijnders]

<i>gettype()</i> only returns the variable type, not whether the <b>string</b> will evaluate to a valid integer. All form fields are instantiated as <b>string</b> types, so <i>gettype($formfield)</i> will always return <b>"string"</b>.

<i>is_int()</i> only works in PHP4.

-- Rich

[rrijnders]

check that...

I meant <i>is_numeric()</i> only works in PHP4.