number of concurrent sessions?

Anon

how can i get the number of concurrent sessions? sure i could count the number or files in the directly, but that seems silly and i'm sure PHP keeps track of it.

thanks

[deleted]

Actually I don't think PHP keeps track of it, because there is notreally such a thing as 'concurrent sessions'.

The only 'concurrency' is in the fact that some sessionid's haven't expired yet.
Remember, sessions ususally don't end, they timeout.

Anon

hi,

do u want to count the total no. of users currently seeing a particular page?

vishwa vivek

Anon

i understand that... i wanted non-timed-out sessions... i wrote this code: seems to work.

if i make sessions time out after 5 minutes, and a users hits the page every 4 minutes, the session will never time out right? it is 5 minutes from the last access, am i right?

<?php
chdir("/php/sessions");
$dir = dir(".");
$files = array();
while($file = $dir->read()) if ($file != "." && $file != "..") $files[] = filesize($file);
$dir->close();
sort($files);
for($i=0; $test_size = each($files); $i++) if($test_size['value']) break;
$registered = count($files) - $i;
echo "$registered registered users online and $i guests";
?>

Anon

actually, the entire site... how many are logged on, and how many are just viewing.

Anon

actually, because most of the time there are more guests than logged in users, this code is optimized:

<?php
chdir("/php/sessions");
$dir = dir(".");
$files = array();
while($file = $dir->read()) if ($file != "." && $file != "..") $files[] = filesize($file);
$dir->close();
rsort($files);
for($i=0; $test_size = each($files); $i++) if(!$test_size['value']) break;
$registered = count($files) - $i;
echo "$registered registered users online and $i guests";
?>

Anon

threw that up too fast:

correct code follows:

<?php
$dir = dir("/php/sessions");
$files = array();
while($file = $dir->read()) if ($file != "." && $file != "..") $files[] = filesize("c:\php\sessions\".$file);
$dir->close();
rsort($files);
for($registered=0; $test_size = each($files); $registered++) if(!$test_size['value']) break;
$guests = count($files) - $registered;
echo "$registered registered users online and $guests guests";
?>

Anon

Actually, your code is sort of pointless, because of the way sessions are done in PHP. There is a setting which determines the probability of a "garbage collection" happening, and this probability will influence how often old session files get deleted. You can of course set this value to 1, meaning that every time someone loads a page, garbage collection will run, but this put a rather nasty overhead on your page.

If you want to do "number of current users on this page/site" (again, rather pointless), then search old articles in this forum, people have solved this hundreds of times before, no need to reinvent the wheel.