a problem with list()

[Anon]

Hi, I have a lil code snipped in which I try to learn list()

---

$var1 = array();

$var1[0][0] = "aaa";
$var1[0][1] = "bbb";
$var1[0][2] = "ccc";

list($c, $cc, $ccc) = $var1;

$x = "c";
for ($i=1; $i<=3; $i++)
{
echo "--->".$$x."<br>";
$x.= "c";

}

What I expect is, that this scripts
outputs

-->aaa
-->bbb
-->ccc

but it outputs

-->Array
-->
-->

What do I wrong?

thx

[[deleted]]

Quite simple.
You are creating a two-dimentional array, and then readin it asif it was one-dimentional.

[Anon]

Well, that is what I intendet to do.

I thought that in the firts line of tjis 'table' (array) are the values
aaa;bbb;ccc and these Values sould be 'exploded' by list into the variables
$c, $cc and $ccc. When I refer the PHP documentation it is - for me - the same!
exept that the array is provided by an mysql_fetch_row ?!

Could you please correct the code a bit, I think then I'll understand.

thx

[powerlord]

You also need to use each() when using a two dimensional array, as the code for mysql_fetch_array will show you.

list($c, $cc, $ccc) = each($var1);

should do what you want.

If you have more than one row, you'd need to put that as an argument in a while.

[[deleted]]

$var1 = array();

$var1[0][0] = "aaa";
$var1[0][1] = "bbb";
$var1[0][2] = "ccc";

list($c, $cc, $ccc) = $var1;
// You can't do this, because you only created $var1 as an array of one element
// See what the array contains:

echo '<pre>';
echo "var1 contains:<BR>\n";
print_r($var1);
echo '</pre>';

// You stored the 'aaa' 'bbb' 'ccc' in an array that's in the first element of $var1, so that
// where you should fetch it from.
list($c, $cc, $ccc) = $var1[0];

$x = "c";
for ($i=1; $i<=3; $i++)
{
echo "--->".$$x."<br>";
$x.= "c";
}

[Anon]

Thx! That was it

[Anon]

thx thath helped!