fopen

[scuba]

Hi,
When I use this code to read in the contents of another file:.....

$contents = (\"\$fp = fopen(\'/home/supracore/public_html/smac/test1/setupfile.php\', \'r\');
eval (\'\$fp = \\'$fp\\');
echo (\$fp)\");

.... the output on my browser comes out as:

$fp = fopen(\'/home/supracore/public_html/smac/test1/setupfile.php\', \'r\'); eval (\'$fp = \\'\\'); echo ($fp)

....instead of actually reading in an processing the file it is supposed to. Can anyone help? This is a problem that has plagued me for 3 days now.

Thanks in Advance
Steve

[Anon]

I think your logic is wrong. Here is how I've always used fopen and I've never had a problem.

$fp = fopen("/home/supracore/public_html/smac/test1/setupfile.php", "r");

$contents = "Error Opening File";

if ($fp) {
$contents = "";
while ($line = fgets($fp)) {
$contents .= $line;
}
}

echo $contents;

I don't know what you were trying to do, but it looks weird to me. fopen() returns a file handle which you will never be able to echo out to the screen.

[scuba]

Please ignore the slashes in my code, for some reason when I posted my code, some slashes were automatically added.

[scuba]

Hi Rob,

What I'm trying to do here is:

I developed a script that creates a directory and an index.php file. This index.php file will read in another file which will in turn make a call to a database to download a file store on there.

What seems to keep happening is that the php isn't being processed and just the text is remaining.

[lionheart]

$fd = fopen ($filename, "r");
$contents = fread ($fd, filesize ($filename));
fclose ($fd);
$contents = parse_file($contents);
eval ("?>$contents");
exit;

[scuba]

Hi,

I tried that code but I get:

Call to undefined function: parse_file()

is there another function for this in PHP ?

[lionheart]

Sorry for confusing you.

parse_file is just a function made by yourself, representing that you can do some things with $content (e.g. ereg_replace links into hyperlinks) before you serve it to the client.

See ya,

Richard