Help with GLOBAL scope

Anon

I'm can't seem to use variable variables to declare a variable GLOBAL. Is it even possible to do this. I have been able to successfully do this function if I make manually declare each variable GLOBAL, but that seems to create a lot of bloat in the code.
I'd also like to be able to use a variable variable to make the array GLOBAL in scope as I've only been successful using this function if I also make the array GLOBAL, even when the array is mentioned in the parameters of the function.

FUNCTION insert_info_into_session($array_w_q_data,$num_of_cookie) {
GLOBAL ${$array_w_q_data};

GLOBAL $info{$num_of_cookie};
$info{$num_of_cookie} = serialize(${$array_w_q_data});

session_register("$info_1");

return;
};

Why does this not work. It seems to be set up properly.
I've tried 10 different variant of this and just can't get anyhing to work.

Please help,
Bryan

Anon

Are you not getting the session variable set that you are expecting? If this is the case then the problem probably lies here:

session_register("$info_1");

You are registering the variable name that is found in the variable $info_1, but I see no refrence to $info_1 in your code snippet. So if $num_of_cookie doesn't equal 1 then you are trying to register something that doesn't exist.

Anon

Oops,
Sorry about that.
$info_1 would be (create?) when you run call this function like this:

insert_info_into_session('cart',1);

In theory, this would set $info_1 to GLOBAL scope in this line:
GLOBAL $info_{$num_of_cookie};

but it's not working for me.

Any ideas why?
I've looked at PHP.net and can't even find a reference to GLOBAL.

Bryan
p.s. Here is the code again, slightly modified.🙂

FUNCTION insert_info_into_session($array_w_q_data,$num_of_cookie) {
GLOBAL ${$array_w_q_data};

GLOBAL $info{$num_of_cookie};
$info{$num_of_cookie} = serialize(${$array_w_q_data});

session_register("$info_{$num_of_cookie} ");

return;
};

Anon

I've never tried to globalize a variable that I didn't know the name of so I don't know if it can be done.

Have you put in any debugging code to see what values you are playing with, just incase this is working, but your problem is somewhere else.

Anon

The variable would have a name would fall in a range between $info_1 and $info_20. There are only 20 different possibilities.

Now the debugging code, I've not used any of that. I have inserted echo statements in a an attempt to figure out what is being the variable is at differnt points.
I'm not really sure how to do this in this instance unless I do this:
echo $info_1;

Thanks
Bryan