using IF and THEN

raisinlove

Hi, this shoudl be basic stuff but it doesnt seem to work. I dont know the exact syntax to use. What I`d like to do is have an IF statement determined by variable "$id".

If variable $id equals "1"
Then the variable $menu should
equal array1 (where array one is where I actually put the entire array)

and so on with $id = 2, $id = 3...

Is this clear? What is the syntax I should use?

Thanks,
-steph

[deleted]

Did you read this?
http://www.php.net:8000/manual/en/html/control-structures.html

raisinlove

Yes but it didn`t help much. Here's my code:

<?php
if ($id = "1"){
$style = array(0=>"bgcolor='#666666' class='menuon'",
1=>"bgcolor='#666666' class='menuon'",
2=>"bgcolor='#ffffff' class='menuoff'");
} else {
$style = array(0=>"bgcolor='#666666' class='menuon'",
1=>"bgcolor='#ffffff' class='menuoff'",
2=>"bgcolor='#ffffff' class='menuoff'");
}
?>

In other words, the value of $id will determine the value of $style.

Is there an easier way to do this perhaps?

smarlowe

http://www.php.net:8000/manual/en/html/control-structures.switch.html

shows all you need to know to make this work.

Anon

The test for equality in this example should be :

if ($id == "1"){

if you only use one '=' character it will be an assignment statement, not an equality test.

dolphinsnot

It's not going to work as long as you've got

if($blah = 1){}

because the equal sign assigns $blah a value of '1' which then evaluates to 'TRUE' inside the if statement...

if($blah == 1){}

= assigns values to stuff
== means 'is equal to'

-dolphinsnot