more IF/THEN woes...

raisinlove

I'm working on a pretty complex script but what I'm having the most trouble with is an IF THEN segment which I've simplified below:

<?php
if ($id = 1)
{ $variable = one ;}
if ($id = 2)
{$variable = two ;}
if ($id = 3)
{$variable = three ;}
else
{$variable = none ;}
print $variable;
?>

(The $id variable is called in the URL in this simpler version of what I'm attempting)

Anyway, any variable I use, be it $id=1, $id=2, $id=3 or none at all, I keep getting the results from the last element: "three".

I'm sure there's something I need to add here yet I havent found any answers in the manual so far.
Does anyone know?
thank you!

Anon

Your code should be like this:

<?php
if($id == 1)
{ }

If you are comparing two things, use double equals, otherwise you are setting $id to whatever is on the other side, for example,
if($id = 1)

sets $id to 1

raisinlove

Ah, you're right! But that's how I originaly did it and all it returned was "none", regardless of what $id is set to.
Try it...

junebug

there are two things you can do. one you can use switch() which i like much better.

http://www.php.net/switch

or, if you want to stay with if else, do this:

if($id == 1)
$var = 'one';

elseif($id == 2)
$var = 'two';

elseif($id == 3)
$var = 'three';

else
$var = 'none';

print $var;

raisinlove

I tried the switch option but couldnt get it to work. What would you suggest for it?

junebug

switch($id){
case 1:
$var = 'one';
break;
case 2:
$var = 'two';
break;
case 3:
$var = 'three';
break;
default:
$var = 'none';
break;
}

dolphinsnot

http://www.phpbuilder.com/forum/read.php3?num=2&id=146798&loc=0&thread=146798

i suggest you check this link out...

it\'s the post you made yesterday where we already answered this question for you.

-dolphinsnot

raisinlove

Yes, thanks, I just thought I would put it into a different context since the first way didnt work. But Chris set me in the right direction, I understand how it works much better now...
sorry about that...