Unix Date command

[Anon]

Hi there,

Is there any ways to diplay a specific date in julian format. for example, 01/03/1999 in Julian date format. I know we can do it for current date like date + %j, but don't know how to do it for previous or future date.
( I need a way to find out from 01/01/1999 to 03/16/1999 has 75 days)

Could you please help me out. -Thanks a lot

Rathika

[Anon]

make a timestamp from us using mktime()

then give the timestamp to date() as the second parameter, so you can use date() for future or past times, too.

see reference and postings! there are many useful code snippets.

[Anon]

oh god - no not from us! from it - sorry.

[Anon]

My code says it's 74 days. Not sure if that's correct though.

$old = "01/01/1999";
$new = "03/16/1999";

list($m1, $d1, $y1) = explode("/", $old);
list($m2, $d2, $y2) = explode("/", $new);

$oldstamp = mktime(0, 0, 0, $m1, $d1, $y1);
$newstamp = mktime(0, 0, 0, $m2, $d2, $y2);

echo ($newstamp - $oldstamp) / 86400;

[beettlle]

Why devide by 86400 the diference between both times?