Calling function outside a class functio

[Anon]

Hy,

Is it possible to open a variabele outside a class function? Like this:

$word = "hello";

class speak
{
function hello() {
echo $foo;
}
};

say = new speak;
say->hello();

This will give an error

[junebug]

$say = new speak;
$say->hello();

[Anon]

It's just an example I made fast, it's just meaned to show you what I mean.

chris wrote:

$say = new speak;
$say->hello();

[junebug]

i know and what i am saying is that this will cause an error:

say = new speak;
say->hello();

this is the proper syntax and won't cause an error:

$say = new speak;
$say->hello();

now what exactly you are asking if you can do i don't think i understand. you have

$word = "hello";

then you define the class and create the object and all that. but you call the hello method and i don't see what you want it to do. the $foo variable is not set anywhere. so what do you want it to do?

[Anon]

You still don't know what I mean, but I found the solution already. The problem was: How do I get an outside variable from whithin a function.

Like this:

$var = "test";

function Speak() {
echo $var; // error
}

Solution:

$var = "test";

function Speak() {
global $var;
echo $var; // Will print "test"
}

chris wrote:

i know and what i am saying is that this will cause an error:

say = new speak;
say->hello();

this is the proper syntax and won't cause an error:

$say = new speak;
$say->hello();

now what exactly you are asking if you can do i don't think i understand. you have

$word = "hello";

then you define the class and create the object and all that. but you call the hello method and i don't see what you want it to do. the $foo variable is not set anywhere. so what do you want it to do?