Help la, about fsockopen

[phpiscool]

sorry to post so much rubbish, but .....

i am learning socket functions, but i was beaten by the first one...............

just a simple test

<?
$fp = fsockopen ("www.php.net", 80, $errno, $errstr, 30);
if (!$fp) {
echo "$errstr ($errno)<br>\n";
}else echo "OK";

but:
$errstr is empty , and $errno=0

can anybody tell me why?

thanx very very much

thanx veryvery very very very much

[Anon]

PHP manual says:

"Note that the errno and errstr arguments must be passed by reference."

So try

$fp = fsockopen ("www.php.net", 80, &$errno, &$errstr, 30);