Date Functions ?

[Anon]

Hi there ,

I have a date variable $Dstamp;
I ' m looking for a next day function ?

For example :
1-august-2001
$Dstamp = $Dstamp+1;
this gives me only the day (in this case 2)

Afterward I want to extract this date in a day , month and year variable?

How can I do this?

Many THX

Gerry

[toma42]

Check out the DATE/calc.php script in PEAR (distrubited with php).

[cordex]

check out the date() and mktime() functions

[Anon]

I 'm a little bit disappointed can nobody help me

[Anon]

I'm a litte bit disappointed can nobody help me?

[cordex]

We've provided you with a substantial starting point. You've been given two possible solutions that will require a small amount of work on your part. If your question is: "will no one do all my thinking and coding for me?" then the answer is probably not. Two people have helped you. Now you're just whining.

-Ben

[Anon]

If you call this support , my company will be broke ...
Better no help than no good help.
An answers like yours means to me that you do really don 't know it either
I 'll try a better newsgroup....

[toma42]

You obviously didn't look into the solutions we gave you. Hopefully you don't need to make a living off of your programming....

From my first post, the class date_calc has the following functions that would do what you need, jerk:

nextWeekday
Returns date of the next weekday of given date,
skipping from Friday to Monday.

nextDayOfWeek
Returns date of the next specific day of the week
from the given date.

nextDay
* Returns date of day after given date.

Are these not good enough for you or did you want someone to code it into your app for you?

Don't be lazy.

[cordex]

In addition to Tom's very helpful post, mine works too: the mktime() function will create a unix timestamp for any given date (use time()+86400 with the date function to get the date for 24 hours from the current time, place that information into the mktime() function and you've got a timestamp for tomorrow) and you can use date() again to format it any damn way you please.

Both of us gave you a flippin' answer that would work for any decent programmer - even a beginner - and you come back with that crap? Tom even provided you with a series of PRE-WRITTEN functions so you didn't even have to know any more then the basics!

If you want support that your company can use so you don't have to work, you can hire me. This board isn't for providing a free programming service for your company. It's for supporting programmers and developers (both experienced and just beginning) who can in turn (if they choose) sell their services. Perhaps you should find a board that supports lamers and leeches.

I'm not paid to do your bloody work for you, I take the time out of my day because I usually enjoy helping people and because I learned a lot off of this board when I was starting out. You've no right to bitch and moan about two good responses because you're too bloody lazy to use them.

-Ben

[Anon]

This is my last answer on your reaction.
First of all , last year I helped about 500 people with my answers in newsgroups.
This year I have helped over 300 people.
The support I give is REAL working code with a REAL working example.
I believe that just saying read the manual on page ... is not helpfull to people
at all. And sure it is not a question about being lazy or not.
It is about helping people ....and words only is 'nt enough that 's why
I always provide REAL working code and examples.

OK what about PRE-WRITTEN functions , it was not a bad answer but it is
not working on the server that I 'm working on.
So compiling this pear thing is not an option and much to time-consuming.
PHP is not my thing otherwise I won 't ask questions about it.

BUT you must read this answer :

Dear Gerry ,

I 'm suprized that you post messages in Newsgroups.
But because you have helped me a lot in the past ,
I ' m very happy that I can provide you an answer.
If you need other issues solved relating php you can always
contact me first.

Here we go :

so you have a $Dstamp date variable .....
try next

$NextDay=((strtotime ($Dstamp))+86400);
$format="d-M-y";
$fday="d";
$fmonth="M";
$fyear="y";
$NDAY=date($format,$NextDay);
echo $NDAY;
$Day=date($fday,$NextDay);
echo $Day;
$Mon=date($fmonth,$NextDay);
echo $Mon;
$Year=date($fyear,$NextDay);
echo $Year;

Have Fun ...

Jonathan

AND YES , that was the small detail I was looking after.
I 'm not saying there are other solutions but it helped me out.

If he would said to me try follow functions (strtotime and date) than
it would not helped me...even after studying the functions and find than
the answer by myself.
And no I won 't hire you for 13 lines of code .

Enjoy your day and don 't accuse people from mean things because
they wanted a better answer.

-Gerry

[Anon]

This is my last answer on your reaction.
First of all , last year I helped about 500 people with my answers in newsgroups.
This year I have helped over 300 people.
The support I give is REAL working code with a REAL working example.
I believe that just saying read the manual on page ... is not helpfull to people
at all. And sure it is not a question about being lazy or not.
It is about helping people ....and words only is 'nt enough that 's why
I always provide REAL working code and examples.

OK what about PRE-WRITTEN functions , it was not a bad answer but it is
not working on the server that I 'm working on.
So compiling this pear thing is not an option and much to time-consuming.
PHP is not my thing otherwise I won 't ask questions about it.

BUT you must read this answer :

Dear Gerry ,

I 'm suprized that you post messages in Newsgroups.
But because you have helped me a lot in the past ,
I ' m very happy that I can provide you an answer.
If you need other issues solved relating php you can always
contact me first.

Here we go :

so you have a $Dstamp date variable .....
try next

$NextDay=((strtotime ($Dstamp))+86400);
$format="d-M-y";
$fday="d";
$fmonth="M";
$fyear="y";
$NDAY=date($format,$NextDay);
echo $NDAY;
$Day=date($fday,$NextDay);
echo $Day;
$Mon=date($fmonth,$NextDay);
echo $Mon;
$Year=date($fyear,$NextDay);
echo $Year;

Have Fun ...

Jonathan

AND YES , that was the small detail I was looking after.
I 'm not saying there are other solutions but it helped me out.

If he would said to me try follow functions (strtotime and date) than
it would not helped me...even after studying the functions and find than
the answer by myself.
And no I won 't hire you for 13 lines of code .

Enjoy your day and don 't accuse people from mean things because
they wanted a better answer.

-Gerry