How to pass arguments to a php-script

[Anon]

Hi,

how do i pass arguments to a php-script when it is run from the commandline?

e.g. php.exe -q mytest.php arg1=foo arg2=bar

is this possible? i tried it like the example, but i won't work. any solutions?

Thanks

Servet
(Win2k running PHP 4.06)

[tijger]

hi Servet,

you should read the following article:
http://www.phpbuilder.com/columns/darrell20000319.php3
it contains the info you are looking for.

from commandline:
php.exe -q mytest.php foo bar

in file mytest.php
<?php

$scriptname = $argv[0];
$arg1 = $argv[1];
$arg2 = $argv[2];

echo $arg1 ."\n". $arg2 ."\n";

?>

this will print:
foo
bar

never do something else before you read the array $argv, and remember the first value of the array is always the filename.

greetings