Any reason why....?

[guido88]

Gentlemen:

I have a random image .php script, and it works FINE by itself; however, when I "copy/paste" the code into an HTML page, it doesn't work.

Am I missing something here?

Guido

[djg_uk]

Hi Guido,

What file extension are you using?

Regards,

David.

[[deleted]]

"it doesn't work"

that doesn't really give us much to go by does it....

[guido88]

When I just upload the ".php" file -- everything works JUST FINE. (ie... it pulls from the directory, and randomly generates the image).

However, when I take this SAME code:

<?php

Directory goes here relative to script

$kataloog = '/ad';

Directory should contain only images, else you can add some more filtering

$i = 0;
$kat = opendir ($kataloog);
while ($f = readdir($kat))
{ if ($f != '.' && $f != '..') # Directory should contain only images, else you can add some more filtering
{$nimed[$i++] = $f;}
}
closedir ($kat);
srand((double)microtime()*1000000);
$nimi = $kataloog.'/'.$nimed[rand(0,sizeof($nimed)-1)];
$suurus = GetImageSize ($nimi);
?>
<P><img src="<?php echo $nimi; ?>" <?php echo $suurus[3]; ?> align="left" alt="Advertisement"></p>

---

And I embed it into html (ie... I copy/paste the code into a table) -- the image will not be pulled from the above mentioned directory -- the .php file is in the same directory as the .htm file with the embeded code. I have played with the directory location, but nothing. 🙁

Guido

[guido88]

When I just upload the ".php" file -- everything works JUST FINE. (ie... it pulls from the directory, and randomly generates the image).

However, when I take this SAME code:

<?php

Directory goes here relative to script

$kataloog = '/ad';

Directory should contain only images, else you can add some more filtering

$i = 0;
$kat = opendir ($kataloog);
while ($f = readdir($kat))
{ if ($f != '.' && $f != '..') # Directory should contain only images, else you can add some more filtering
{$nimed[$i++] = $f;}
}
closedir ($kat);
srand((double)microtime()*1000000);
$nimi = $kataloog.'/'.$nimed[rand(0,sizeof($nimed)-1)];
$suurus = GetImageSize ($nimi);
?>
<P><img src="<?php echo $nimi; ?>" <?php echo $suurus[3]; ?> align="left" alt="Advertisement"></p>

---

And I embed it into html (ie... I copy/paste the code into a table) -- the image will not be pulled from the above mentioned directory -- the .php file is in the same directory as the .htm file with the embeded code. I have played with the directory location, but nothing. 🙁

Guido

[Anon]

well, simple. a php script has to have the extension ".php" to be executed by apache, or you have to change the apache config so that it parses ".htm" files for php code as well, but if you have many html files with just plain content that may slow your site down a bit because apache parses every file.

mats99
have more fun!

[Anon]

what does it say when you view source of the html page??

[guido88]

The problem was I simply needed to change the extention .htm to .php -- as someone else mentioned (and I should have known better) -- the PHP engin will only run on PHP files. Duh.

Thanks for the advice everyone!

Guido