Strange thing in if-statement

Anon

Dear Readers,

If doesn't work.. I had this problem before. I posted a message and I got a sollution

---1st I tried this---
if($totaal = 0.7) {
print ("<IMG SRC=tweederdegroenballetje.gif>");
$balletje = $balletje - 1;
}

---2nd I tried this---

if($totaal == 0.7) {
print ("<IMG SRC=tweederdegroenballetje.gif>");
$balletje = $balletje - 1;
}

I tried to put the 0.7 between Quotes (' ') & Double Quotes (" ") but nothing seems to work!

In the first-case it always matches. and in the 2nd case it never matches!

Can anybody help me!?!?

Greetings,

Kasper Schoonman (16yr)

Anon

Sorry People I made a mistake,

When I define the variable $totaal as 0.7 it works.. So I thought it had to be something with my string.. but when I print the variable to the screen.. I see it's 0.7 ..

I even did print ("'$totaal'");

to be sure that there are no thing before or after.. but I see it's 0.7

What to do?

Greetings,

Kasper

smarlowe

You might need to cast your variables to be sure PHP treats them right.

I.e.:

if ((int)$somvar==(int)$othervar){
dosomethinghere();
}

The description is here:

http://www.php.net/manual/en/language.types.type-juggling.php

Anon

THX Scott,

I will try that!

Greetings,

Kasper (16yr)