Function scope

[Anon]

Please tell me what the result of this is and why? Thanks.

function f($x, $y) {
$a = $x + 2;
$x += 2;
$y = 2 * $x;
return ($x);
}

$a = 1;
$b = 2;
$c = f($a, $b);
print("result is $a, $b, $c, $x, $y \n");

[nightowl]

$a and $b are not changed, so they remain 1 and 2. $c becomes equal to the $x in the function, which would be 3. $x and $y are unknown out of the function, so the are NULL.

what was this all about ???

[Anon]

Thanks. Checking that my lecture note was wrong as I thought! Stupid lecturer...