How to passing vars thru exec

[Anon]

I does one pass vars when using the exec function ?
I've tried:
exec("/usr/bin/php /home/www/test.php '$myvars'");
the script "test.php" executes but the vars are not passed on/available!
I must use exec because this script must execute in the background.

Thanks,
Peter
n

[znouza]

when calling php script through shell exec, your passed variables will be available as
$argv[x]

where

$argv[0] is the name of script ($PHP_SELF)
$argv[1] is the first argument
$argv[n] is the n-th argument

$argc contains no of arguments passed (including $argv[0]).

so, when you're calling
exec("php my_script.php arg1 arg2 arg3");
then
$argc=4;
$argv[1]="arg1";
$argv[2]="arg2";
...

[Anon]

Tom, I think I know what you mean !

Is the following correct ?

<? // test1.php
$subjet="exec test";
$Fname=Robert;
$Lname=Johnson;
$Addr="2 any street";
$City="My Town";

$message1=$subject;
$message2= "fname = $Fname\rlname = $Lname\r";
$message3= "Addr: $Addr\r\nCity:$City\n";
$message4= "This message was generated by my test\n";
// execute test2.php in background while test1.php continues
exec("/usr/bin/php /home/www/test2.php
$message1 $message2 $message3 $message4");
//script continues ......
?>

<? // test2.php
@mail("[e-mail]","$message[0]", "$message[1] $message[2] $message[3]$message[4]", "From: [e-mail]");
?>

Thanks,
Peter

[znouza]

no.
look here (php manual)
http://php.net/manual/en/language.variables.predefined.php#language.variables.predefined.php

"<b>$argv</b>
Array of arguments passed to the script. When the script is run on the command line, this gives C-style access to the command line parameters. When called via the GET method, this will contain the query string
"

so in test2.php you HAVE TO USE $argv[1]...$argv[n] instead of $message[0].

[Anon]

Thannnnnnnnnnnkkkkkkkkkkkkkkkkkkssssss!!!

I was looking at how to pass arguments from a HTML file to a PHP file. I looked all over the PHP manual and there was nothing there. I looked all over my textbook, there was nothing there. I browse this message board, and viola, there lies the answer!

Thanks a bunch Tom, I've been looking half the day for this!

[Anon]

Tom,

I've got it working like this:
exec("/usr/bin/php -q ./test2.php '$message1 $message2 $message3 $footer'");

<? // test2.php
@mail("[e-mail]","$argv[1]", "$argv[2] $argv[3] $argv[4]", "From: [e-mail]");
?>

what does "-q" do ?

Thank you very much,
Peter

[znouza]

salome:~/public_html$ php -?
Usage: php [-q] [-h] [-s] [-v] [-i] [-f <file>] | {<file> [args...]}
-q Quiet-mode. Suppress HTTP Header output.
-s Display colour syntax highlighted source.
-f<file> Parse <file>. Implies `-q'
-v Version number
-p Pretokenize a script (creates a .php3p file)
-e Execute a pretokenized (.php3p) script
-c<path> Look for php3.ini file in this directory
-i PHP information
-h This help