variable driven image?

[Anon]

Hi,

I am using php to pull results off a mysql database. I am using a single php/html file to generate a number of different display_result pages (passing a different variable onto the file when calling it to display a different set of results).

I'd like to add a different graphic for each different results page and I am thinking that to do this from a single php file my image has to be driven by the variable.

So let's say $var1=setA, I can name the image corresponding to the results page generated by the setA variable setA.gif, and then point to the image by using $var1.gif. Am I trying to do the impossible? because I can't get it to work.

My line in the php/html file is:

print "<img src=setA.gif>";

and this of course works fine, but

print "<img src=$var.gif>";

gets me nowhere.

Thanks in advance and sorry if this is a stupid question.

[mithril]

Soloman,

You need to concatenate $var into the string. Changing:

&nbsp;&nbsp;print "<img src=$var.gif>";

to

&nbsp;&nbsp;print "<img src=" . $var . ".gif>";

should do the trick. HTH.

geoff