array problem

[Anon]

ok, i have a data file that looks like this:

%jim#[e-mail]#jim comments
%bob#[e-mail]#bob comments

and my code looks like this:

<?

// location of entry file
$filelocation = "data.txt";

// open and read entry file
$newfile = fopen($filelocation,"r");
$content = fread($newfile, filesize($filelocation));
fclose($newfile);

// remove slashes
$content = stripslashes($content);

// put entries in array
$lines = explode("%",$content);

echo "<p>$lines[0]</p>";

?>

The problem is $lines[0] does not exist. For some reason the array starts at $lines[1]. If I find the sizeof() of $lines after I explode $content it says 3 but it should say 1! Why? Help me. Thanks. -Ben

[daus95]

after reading the file, $content would become:

$content = "%jim#[e-mail]#jim comments%bob#[e-mail]#bob comments"

so, exploding it by % using command:

$lines = explode("%",$content);

would make $lines:

$lines [0] = '';
$lines [1] = 'jim#[e-mail]#jim comments';
$lines [2] = 'bob#[e-mail]#bob comments';

it means, sizeof($lines) = 3

[Anon]

Your problem is with explode.

Let's say you have this code:

$msg = "1,2";
$arr = explore(',', $msg);

then
$arr[0] == '1'
$arr[1] == '2'

right?

Now, if you have this:

$msg = ",2";
$arr = explore(',', $msg);

then
$arr[0] == ''
$arr[1] == '2'

because you're splitting in the comma, and before the comma there's nothing, so $arr[0] is ''.

Now, in your code, $message becomes this:

$message = "%some stuff\n%some stuff2"

right?
so when you do explode("%", $message), the first element of the array will be empty.

You might want to take a look at the function file():
http://www.php.net/manual/en/function.file.php

Diego

[Anon]

You wouldn't need the % to begin with, if you used the function file($filelocation) to open the file.

From the manual:
"Identical to readfile(), except that file() returns the file in an array. Each element of the array corresponds to a line in the file, with the newline still attached."