strip <% out of text file...

[Anon]

lets say i have a file name like /usr/tmp/blah, could someone write a function that takes in the file name, and returns the name of a temp file that has been created that is identical to the original file, except all occurances of <% have been stripped out?

I tried this, and think i have a working version, but it is extremely slow and parses each line of the file... someone has got to know a better way.

thanks!

[Anon]

the absolutely fastest way to do it, is to write a program i C and then call that from php with system() or similar.

#include<stdio.h>

int main (int argc, char argv[])
{
FILE fp, *ofp;
char[100] outfile;
char buffer1, buffer2;

strcpy(outfile, argv[1]0;
strcat(outfile, "2");

fp = fopen(argv[1], "r");
ofp = fopen(outfile, "w");

while(!feof(fp))

{
buffer1 = fgetc(fp);
buffer2 = fgetc(fp);

if((buffer1 != '<')&&(buffer2 != '%'))
{
fputc(buffer1, ofp);

fputc(buffer2, ofp);
}
}
fclose(fp);
fclose(ofp);

printf("%s",outfile);
return 1;
}

that is totally off the top of my head and completely untested, but it should work. although this is probably far from the fastest algorithm, the "power of c" will more than make up for it.

you will want to compile it, put it someplace accessible by apache and then call it with popen() so you can harvest the output and get the file name.

please note that there is no file locking on this whatsoever and the whole thing is completely devoid of any meaningful error checking. you'll definitely have to beef it up a bit!

-frymaster

[khaine]

The C program would work but you can do it quite fast in php

<?

$filename="/path/to/file/filename.txt";
$filename2="/path/to/file/filename2.txt";
$fpr=fopen($filename, "r") or die();
$fpw=fopen($filename2, "w") or die();

fwrite($fpw, str_replace("<%", "", fread($fpr, filesize($filename)));

fclose($fpr);
fclose($fpw);

?>

It just reads the entire filein replaces the string and dumps it back out in one go.

Mark.