$picture_type

[Anon]

Hey guys,

I keep getting this error:

Undefined variable: picture_type in /blah/blah/script.php

The script is taking a multi-part form field and seems to work except that PHP doesn't know this built-in variable (I thought!)

Here is the bit of code where it is happening:

if ( ('$frm[picture]') && ('$frm[picture]' != "none") ) {

if (!$id)
$id = mysql_insert_id();

$type = basename($picture_type);

switch ($type) {
case "jpeg":
case "pjpeg": $filename = "pictures/$id.jpg";
copy ('frm[$picture]', $filename);
$sql = "update products set picture = '$filename' where id = $id";
$result = mysql_query($sql, $conn);
break;
default: print "Invalid picture format: $picture_type";
}
}

Any ideas?

[matto]

hi!

1. check if "picture" is the file input name.
2. according to http://www.php.net/manual/en/features.file-upload.php :

"$userfile_type - The mime type of the file if the browser provided this information. An example would be "image/gif"."

so, you can't get a basename of a file type.

3. if the variable really is unknown, there's a hint in the url mentioned above:

"In PHP, the following variables will be defined within the destination script upon a successful upload, assuming that register_globals is turned on in php.ini."

hope that helps.