css/php

[Anon]

What is the proper syntax to include link an external css page to a php script?

[[deleted]]

What exactly do you want to do?

[Anon]

I have a stylesheet saved on my server. It's called main.css. On a static page I call it in the header using <link rel=stylesheet.. etc>

How would I include it in my php script? It doesn't work when I include it the way I do on a static page.

[lucianoes]

If it "doesn't work when you include it the way you do on a static page", chances are you're treating the reference to your CSS as a PHP command. Try either of these suggestions:
Print it with echo:
echo "<link rel="stylesheet" type="text/css" href="main.css">";

that is not going to work because of the "" marks inside the echo command. So you'd have to use:
echo "<link rel=\"stylesheet\" type=\"text/css\" href=\"main.css\">";

The \ symbol forces PHP to treat the next character as nothing but a character, removing of all its effect in the syntax.

You can also use the <? ?> delimiters to get out of PHP mode, declare your CSS and get into PHP mode again:
<?php
...(some PHP code)
?>
<link rel="stylesheet" type="text/css" href="main.css">
<? ...(some more PHP code)...
?>

HTH,
Luciano ES

[[deleted]]

CSS is an HTML thing, so you have to make sure that the OUTPUT of your scripts is correct HTML, and that the stylesheet is included at the correct place, just like wth a static page.