help

Anon

I want to pass an array through hidden fields.but I'm unable to do that.
the keyword "Array" appears when I tried to display the array in the other script
I also want to assign the values of the array to a varible.I'm pasting my code.Plz do check it & CORRECT it.
& also tell my mistake.there are two scripts.1) display.php 2) save.php
I'm writting this code inhurry,so neglect small errors.Thanx

//display.php
<head>hi </head>
<body>
<?php
$countries=array(1,2,4,6);
?>
<form action="save.php" method="post" >
<input type="hidden" name="places[]" value="<?php echo $countries; ?>">
<input type="submit value="Save">
</form> </body>

//save.php
<?php
$value="";
do {$val=current($places);
echo("Element is $val<br>");
$value.=$val;
} while(next($places));
?>

[deleted]

It is impossible to print an array using echo.

echo $aArray;

is not possible.

You can either print each element of the array as a seperate hidden field;

<input type=hidden name=something[] value=<? echo $aArray[1];?>>
<input type=hidden name=something[] value=<? echo $aArray[2];?>>
etc..

or use the serialize function to translate the array into a single string that you can print.

Anon

thanx for the help.I have still problem relating to the older one.
I passed the values of array through hidden fields with the help of a loop.
In the next script.I assign these elements to a variable.when I tried to store that value in the database(Ms Access) then not full variable was present there.Only the part of first element was there.The datatype of that field is "Memo" & the string variable is very much smaller that .
Why this is happening?? Plz do solve my this problem.
thanx in advance