checkboxes

Anon

i want form handler script to check if two specific checkboxes are checked.
the form have 14 checkboxes named chkbox[].
it also have 14 drop-dows menu named komatia[].
if a chkbox is checked it prints the value of the checkbox and the value of the drop-down menu.
but if checkbox 7 or 8 is checked i want it to print the value of the 7th or 8th drop downmenu AND the value of one radiobox (for each checkbox) name kbsradio[] for the 7th and kfbradio[] for the 8th.
This is what i wrote.:
if (&chkbox[7].checked==true)
{
PRINT "$chkbox[7] kbsradio1 "
}

if (&chkbox[8].checked==true)
{
PRINT "$chkbox[8] kfbradio1 "
}
else
{
$count=count($chkbox);
for ($i=0; $i<$count; $i++)
{
PRINT "$chkbox[$i] ($komatia[$i]) ";
}
}

IT MAY BE TOO EASY BUT I AM NEW TO PHP.
THIS IS MY SECOND SCRIPT.
THANK YOU.

techek

First of all : PHP and JavaScript are two entirely different things. So skip the ".checked"-syntax and test if the chkbox has a value set or not.

If a checkbox is checked, "checked" is added like this :

<input name="chkbox" type="checkbox" checked value="on">Whatever

If not, leave "checked" out.

To see if the checkbox is checked or not, look at the value. If it's "on" it's checked if not, it's unchecked :

<?php
if ($chkbox == 'on') {
echo "I'm checked!";
} else {
echo "I'm NOT checked!";
}
?>

If you need a more specific example, contact me and I'll whip up some code.

kosmidd

this is the code i needed.
$count=count($chkbox);
for ($i=0; $i<$count; $i++)
{
if ($chkbox[$i] != 'value1' && $chkbox[$i] != value2')
{
PRINT "$chkbox[$i] ($komatia[$i]) ";
}
else if ($chkbox[$i] == value1)')
{
PRINT "$chkbox[$i] $kbsradio ($komatia[$i]) ";
}
else if ($chkbox[$i] == value2')
{
PRINT "$chkbox[$i] $kfbradio ($komatia[$i]) ";
}
}

thank you very much