Query text file for remote user and...

Anon

So I've got a page in a htpasswd protected directory. When the user accesses the page, I want to query a text file to see if their name is in there. If it is, I want to print an instructional greeting.

Here's what I've got so far, but it's not working.... The problem is with USERNAME. I need that to change each time -- to reflect the name they logged in with -- that would be REMOTE_USER. But I can't seem to get the syntax right. If I replace user name with the actual static name of a user -- like USER11, it works fine.

$file="/path and name of file";
$fd = fopen ($file, "r");
$contents = file($file);
$number = count($contents);
for($i=0;$i<$number;$i++) { if(strstr($contents[$i],'USERNAME')) print ("<B>Instructional Greeting</B>"); }

Any ideas?
Thanks,
averick

Anon

Try using the variable in $PHP_AUTH_USER .. this should contain the username that was logged in.

Hope that helps!

Chris King

Anon

Thanks Chris,
That's a no-go too.

Elsewhere on the page, I can display the remote user with:

start php
echo $REMOTE_USER;
end php

I'm just not introducing it correctly into the if statement.

Anon

Got it Chris,
Silly me... Turns out I just had to get rid of the ' ' on either side or $REMOTE_USER. Those were fine when I was using a static user name. But not good in this scenario.

$file="/path and file name";
$fd = fopen ($file, "r");
$contents = file($file);
$number = count($contents);
for($i=0;$i<$number;$i++) { if(strstr($contents[$i],$REMOTE_USER)) print ("Instructional Greeting with HTML code"); }

No doubt, your suggested $PHP_AUTH_USER would work as well in the new scenario.

Thanks,
averick

Anon

Hmmmm.... And now that I've got that done.... Does anyone have any idea how I'm going to build in an else statement?

Obviously PHP aint my bag. I'm trying ideas at random. But it's late and things are getting a bit fuzzy.